#include <stdio.h>
#include <time.h>
#include <math.h>
#include <sys/time.h>
      
        
          | int frequency_of_primes | ( | int | n | ) |  | 
      
 
   39     for (i=2; i<=n; ++i) for (j=(int)sqrt(i);j>1;--j) 
if (i%j==0) {--
freq; 
break;}
 int i
Definition: rw_test.cpp:37
JHUFF_TBL long freq[]
Definition: jchuff.h:47
 
 
      
        
          | int timeval_subtract | ( | struct timeval * | result, | 
        
          |  |  | struct timeval * | x, | 
        
          |  |  | struct timeval * | y | 
        
          |  | ) |  |  | 
      
 
   46     if (
x->tv_usec < 
y->tv_usec) {
    47         int nsec = (
y->tv_usec - 
x->tv_usec) / 1000000 + 1;
    48         y->tv_usec -= 1000000 * nsec;
    51     if (
x->tv_usec - 
y->tv_usec > 1000000) {
    52         int nsec = (
y->tv_usec - 
x->tv_usec) / 1000000;
    53         y->tv_usec += 1000000 * nsec;
    59     result->tv_sec = 
x->tv_sec - 
y->tv_sec;
    60     result->tv_usec = 
x->tv_usec - 
y->tv_usec;
    63     return x->tv_sec < 
y->tv_sec;
 
 
 
      
        
          | float elapsed_time | ( | struct timeval | dif, | 
        
          |  |  | struct timeval | a, | 
        
          |  |  | struct timeval | b | 
        
          |  | ) |  |  | 
      
 
   72     return -dif.tv_sec*1000.0-dif.tv_usec/1000.0;
 long b
Definition: jpegint.h:371
int timeval_subtract(struct timeval *result, struct timeval *x, struct timeval *y)
Definition: playground/clock_test.cpp:43
Definition: eci2kep_test.cpp:33
 
 
   79     printf (
"Calculating...\n");
    81     struct timeval tv1,tv2,diff;
    89     gettimeofday(&tv1, &tz);
    91     gettimeofday(&tv2, &tz);
    95     tm=localtime(&tv1.tv_sec);
    96     printf(
" %d:%02d:%02d %d \n", (
int)tm->tm_hour, (
int)tm->tm_min, (
int)tm->tm_sec, (
int)tv1.tv_usec);
    98     tm=localtime(&tv2.tv_sec);
    99     printf(
" %d:%02d:%02d %d \n", (
int)tm->tm_hour, (
int)tm->tm_min, (
int)tm->tm_sec, (
int)tv2.tv_usec);
   105     printf(
"It took me %f milliseconds\n", k);
   110     printf (
"The number of primes lower than 100,000 is: %d\n",f);
   111     printf (
"It took me %d clicks (%f seconds). CPS: %f\n",dt,dt/(
double)CLOCKS_PER_SEC,(
double)CLOCKS_PER_SEC);
   115     time_t     now = time(0);
   119     seconds = time (&now);
   120     printf (
"%ld hours since January 1, 1970\n", seconds/3600);
 ElapsedTime dt
Definition: agent_file3.cpp:183
int frequency_of_primes(int n)
Definition: playground/clock_test.cpp:36
float elapsed_time(struct timeval dif, struct timeval a, struct timeval b)
Definition: playground/clock_test.cpp:66